• consecutive odd integer problem find two odd integers the sum of whose squares is 130. (sq)=squared let x= 1st odd int let x+2 The demand for this medicine is perfectly inelastic so long as price is less than the $100 (per day) income of the 100 patients who need to take this drug once a day.
Hence, the 2 consecutive integers are 33 and 34. When added together, they equal 67, and they are consecutive (34 is 1 larger than 33). thanks!
  • …that all Consecutive Odd Integers and Consecutive Even Integers are always two more than the previous number, as Online Math Learning Together we will successfully translate sentences that represent Consecutive Integers and apply them to such questions as finding age of siblings, height...
  • consecutive odd integer problem find two odd integers the sum of whose squares is 130. (sq)=squared let x= 1st odd int let x+2 The demand for this medicine is perfectly inelastic so long as price is less than the $100 (per day) income of the 100 patients who need to take this drug once a day.
  • Let first positive integer be xSo, other positive integer = x + 1According to question,x2 + (x + 1)2 = 365 x2 + x2 + 1 + 2x = 365⇒ 2x2 + 2x – 364 = 0⇒ x2 + x – 182 = 0⇒ x2 + 14x – 13x – 182 = 0⇒ x(x + 14) – 13(x + 14) = 0⇒ (x – 13) (x + 14) = 0⇒ x – 13 = 0or x + 14 = 0⇒ x = 13or x = –14Here x = – 14 does not exist.Therefore, required positive integers are : x = 13 and x + 1 = 13 + 1 = 14.
Second number = Therefore two consecutive positive integers are 13 and 14 whose sum of squares is equal to 365.

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priyaljoseph. let the first no. be - x then next be - x+1. ⇒ since ..it's the square of these nos. ⇒x²+ [ x+1]²=365. ⇒x²+x²+2x+1=365. 2x²+2x-364=0. x²+x-182=0. x²+14x-13x-182=0. therfore the 2 Consecutive nos. are 13 and 14. Chapter 2 section 6 exercise 209

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